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| Candidate |
Votes |
% |
| Hearn (Con) |
13 330 |
39.6 |
| Coady (Lib) |
11 879 |
35.3 |
| Norman (NDP) |
7 989 |
23.7 |
| Willcott (Grn) |
493 |
1.5 |
| Total votes |
33 691 |
100 |
Source: Elections Canada
The variation of the First-past-the-post system used in Japan is referred to as the Single Non-Transferable Vote. The system is used to elect elected members to both the House of Representatives and House of Councillors. In both chambers members are elected from multi-member electorates. Electors have one vote and candidates with the highest number of votes are elected.
Other variations involving multi-member include the Block Vote and the Cumulative Vote systems. In the Block Vote system the elector has as many votes as there are candidates to be elected. Once again the candidates with the highest votes are elected regardless of whether they receive a majority of votes. The Block Vote was the first political system used in Australian Senate elections.
[Three to be elected–elected candidates in bold]
| Candidate |
Vote |
% |
| Findley (ALP) |
217 573 |
48.7 |
| Barker (ALP) |
216 199 |
48.4 |
| Blakey (ALP) |
215 117 |
48.1 |
| Best (Lib) |
213 976 |
47.9 |
| Trenwith (Lib) |
211 058 |
47.2 |
| McCay (Fus) |
195 477 |
43.7 |
| Goldstein (Ind) |
53 583 |
12.0 |
| Ronald (Ind) |
18 380 |
4.1 |
| Total votes |
1 341 363 |
Note: There were 447 121 voters each of whom had three votes, giving 1 341 363 total votes. Percentages shown are percentages of 447 121, indicating the proportion of voters who supported each candidate. As each voter cast three votes, the percentages add up to 300 per cent.
Source: http://psephos.adam-carr.net/countries/a/australia/1910/vic-1910.txt
The Cumulative Vote is of interest to Australia because it is used to elect the Legislative Assembly on Norfolk Island. When the Cumulative Vote is used, voters have the same number of votes as there are positions to fill—in the Norfolk Island case voters have nine votes to elect the nine-person Legislative Assembly. A voter may give one vote to each of nine candidates. On the other hand, the voter may give more than one vote to different candidates, though no more than four votes may be given to any one candidate.
[Nine to be elected–elected candidates in bold]
| Candidate |
Vote |
% |
% of voters |
No. of voters |
| Gardner |
1809 |
17.2 |
59 |
690 |
| Sheridan |
1436 |
13.7 |
50 |
586 |
| Christian |
949 |
9.0 |
35 |
406 |
| Boudan |
838 |
8.0 |
34 |
395 |
| Nobbs |
810 |
7.7 |
32 |
368 |
| Buffet |
755 |
7.2 |
29 |
342 |
| Brown, J |
674 |
6.4 |
26 |
308 |
| Jack |
652 |
6.2 |
27 |
319 |
| Brown, T |
628 |
6.0 |
26 |
308 |
| Nicholas |
566 |
5.4 |
24 |
278 |
| Robinson, R |
512 |
4.9 |
22 |
259 |
| Walsh |
426 |
4.1 |
16 |
190 |
| Jope |
226 |
2.2 |
10 |
112 |
| Robinson, C |
222 |
2.1 |
11 |
124 |
| Total votes |
10 503 |
Source: http://www.gov.nf/Election2004/index.pl
Candidates needed to be one of the leading nine vote winners to gain an Assembly seat. Gardener’s 1809 votes came from 218 voters who gave him four votes, 150 voters who gave him three votes, 165 voters who gave him two votes, and 157 voters who each gave him a single vote—690 voters in all. With the Cumulative Vote some candidates are able to do well despite receiving votes from fewer people than other candidates. In this case the two Browns each had the same number of voters supporting them, although their total votes were 46 apart.
Majority systems require a winning candidate to receive an absolute majority (more than half) of the vote to ensure election. Such a majority can be achieved through a second ballot or by means of preference voting. The second ballot systems are restricted to electing members from single-member electorates while the alternative vote system can be used for both single- and multi-member electorates.
In the Second Ballot system two First-past-the-post elections are scheduled. Candidates who receive more than half of the vote are declared elected. In those electorates where no candidate receives more than half the vote, there will be a second, or run-off, ballot slip. This may be between the top two candidates on the first count, or it may be of candidates who receive a certain percentage of the vote. The Second Ballot system prevents the election of any candidate without an absolute majority of the vote, thus overcoming one of the main criticisms of plurality systems. Second Ballot systems are more likely to be used in presidential elections rather than for legislative elections.
[One to be elected–elected candidate in bold]
| Candidate |
First ballot (%) |
Second. ballot (%) |
| Chirac (RPR) |
19.9 |
82.2 |
| Le Pen (FN) |
16.9 |
17.8 |
| Jospin (PS) |
16.2 |
- |
| Bayrou (UDF) |
6.8 |
- |
| Laguiller (LO) |
5.7 |
- |
| Chevènement (PR) |
5.3 |
- |
| Mamère (LV) |
5.2 |
- |
| Besancenot (LCR) |
4.2 |
- |
| Saint-Josse (C,P,N,T) |
4.2 |
- |
| Madelin (DL) |
3.9 |
- |
| Hue (PCF) |
3.4 |
- |
| Mégret (MNR) |
2.3 |
- |
| Taubira (PRG) |
2.3 |
- |
| Lepage (CAP) |
1.9 |
- |
| Boutin (FRS) |
1.2 |
- |
| Gluckstein (PT) |
0.5 |
- |
Source: http://www.electionworld.org/france.htm.
The Alternative Vote is known to Australians as Preferential Voting and to Americans as Instant Runoff Voting. Preferential Voting is less cumbersome than the Second Ballot system in that it asks the voter to indicate how he or she would vote in the event of his or her first choice candidate being defeated, and of the voter having to choose again from the remaining candidates.
Voters are required to rank candidates in order of preference. This can involve the compulsory allocation of preferences to all candidates (‘compulsory preferential’), or may require the allocation of at least a single preference (‘optional preferential’). If a candidate receives more than 50 per cent of the number 1 votes (the ‘first preferences’), the candidate is elected. If no candidate receives more than 50 per cent of first preference votes, then the candidate with the lowest first preference vote is eliminated and his/her votes are distributed to the remaining candidates on the basis of the second preferences. Candidates are eliminated in this way until one candidate reaches a majority.
[One to be elected–elected candidate in bold]
| Candidates |
First count |
Second count |
Final count |
| Allen (ALP) |
13 129 (41.3%) |
14 507 (45.6) |
15 279 (48.0%) |
| Sykes (Nat) |
8 414 (26.5%) |
8 802 (27.7) |
16 531 (52.0%) |
| Dwyer (Lib) |
8 306 (26.1%) |
8 501 (26.7) |
|
| Stewart (Grn) |
1 961 (6.2%) |
- |
Source: Victorian Electoral Commission
A bewildering number of Proportional Representation systems have been developed in an effort to produce a system under which legislative seats are won by parties in proportion to the proportion of the popular vote they gain. By necessity, this requires more than one vacancy in an electorate, so multi-member electorates are used. Electorates can be:
The more parliamentarians there are to be elected from an electorate, the smaller the percentage of the vote that is required, and the more proportional the overall election result is likely to be. To avoid candidates being elected with very small votes, some countries establish an ‘electoral threshold’. This is the vote that a candidate or party must exceed in order to gain parliamentary representation—examples include 5 per cent in Germany, 4 per cent in Italy, 1.5 per cent in Israel.
Proportional Representation systems can be broadly grouped into two categories: List systems and Single Transferable Vote systems. List systems can be further divided into Largest Remainder and Highest Average categories. List systems may or may not allow the voter to choose between candidates of the same party. List systems can be:
The basic concept of Proportional Representation systems is to allocate seats to parties in the legislature in proportion to the votes cast at an election. To achieve this a number of different and quite complex computational arrangements have been devised. These may or may not include the use of the quota, that is, the number of votes required to obtain a seat.
The method of determining a quota is usually by dividing the number of valid votes by the number of seats to be allocated. This method is often referred to as the Hare quota. Three alternatives to the Hare quota exist: the Hagenbach-Bischoff quota, in which the number of votes is divided by the number of seats plus 1; the Droop quota, in which the number of votes is divided by the number of seats plus 1, and one is added to the quotient; the Imperiali quota, in which the number of votes is divided by the number of seats plus 2. In the following examples, 60,000 valid votes are cast and five seats are to be allocated.
| Method |
Formula |
Calculation |
Quota |
| Hare |
votes/seats |
60 000/5 |
12 000 |
| Hagenbach-Bischoff |
votes/seats+1 |
60 000/6 |
10 000 |
| Droop |
(Votes/seats+1) + 1 |
(60 000/6) + 1 |
10 001 |
| Inperiali |
Votes/seats+2 |
60 000/7 |
8571 |
Source: T. Mackie and R. Rose, The International Almanac of Electoral History, Facts on File, New York, 2nd ed. 1982
The simplest method of allocating seats under proportional representation is the Largest Remainder system. Under this system a quota is established, usually the Hare quota, and is used to determine each party’s allocation. A seat is allocated for each quota that the party obtains. However, this system does not always provide for the allocation of all seats, as a number of votes will be left over after the allocation of full quotas and some small parties will not gain sufficient votes to obtain a full quota. The remaining seat or seats are allocated on the basis of the largest remaining votes after the allocation of full quotas. In the following example five seats are to be allocated but only three parties receive a full quota. The remaining seats are allocated on the basis of the highest remaining votes.
| Party |
Votes |
Hare Quota |
Seats |
Remainder |
Seats |
Total Seats |
| A |
8700 |
4800 |
1 |
3900 |
1 |
2 |
| B |
6800 |
4800 |
1 |
2000 |
0 |
1 |
| C |
5200 |
4800 |
1 |
400 |
0 |
1 |
| D |
3300 |
- |
0 |
3300 |
1 |
1 |
| Total |
24 000 |
5 |
Source: T. Mackie and R. Rose, The International Almanac of Electoral History, Facts on File, New York, 2nd ed. 1982
The above example demonstrates one of the limitations of the Largest Remainder system in ensuring proportionality of representation. In the example, party D receives the same representation as parties B and C even though its vote is substantially lower. The system favours smaller parties over larger parties when using the Hare quota. The relative importance of remainders in the allocation of seats can be reduced by the use of a lower quota (Hagenbach-Bischoff or Droop). Lower quotas result in more seats being allocated on the basis of parties receiving a full quota and fewer being allocated by remainders. However, the use of a lower quota does not always overcome the proportionality problem of the Largest Remainder system. Using the example above, the Droop quota produces exactly the same result as the Hare quota.
To overcome problems associated with the Largest Remainder system the Highest Average system was devised. The object of the Highest Average system is to ensure that when all seats have been allocated the average number of votes required to win one seat shall be as near as possible the same for each party. The Highest Average system can be used with or without a quota. When used with a quota, the system is sometimes referred to as a Hagenbach-Bischoff system. The system derives its name from the method of allocation of seats to parties. Under the system each party’s votes are divided by a series of divisors to produce an average vote. The party were the highest average vote after each stage of the process is allocated a seat. After a party has been allocated a seat its votes are then divided by the next divisor. The Highest Average system has a number of different variations, depending on the divisors used and whether a quota is used or not.
The d’Hondt version uses the numbers 1, 2, 3, 4 etc as its divisions. In the following example the d’Hondt is used without a quota. As in the previous example five seats are to be allocated.
| Party |
Votes |
1st Seat Division |
2nd Seat Division |
3rd Seat Division |
4th Seat Division |
5th Seat Division |
Total |
| A |
8700 |
8700 (1) |
4350 |
4350 |
4350 (4) |
2225 |
2 |
| B |
6800 |
6800 |
6800 (2) |
3400 |
3400 |
3400 (5) |
2 |
| C |
5200 |
5200 |
5200 |
5200 (3) |
2600 |
2600 |
1 |
| D |
3350 |
3350 |
3350 |
3350 |
3350 |
3350 |
0 |
| Total |
24 000 |
5 |
In the above example the first seat divisor is one for all parties. Party A has the highest vote and is allocated a seat. In the second round, votes for party A are divided by two, while all others are divided by one. Party B has the highest vote and is allocated the second seat. The process continues with the divisor for a party increasing by one each time that party is allocated a seat. The above example illustrates the highest average concept of the d’Hondt version. A less complex presentation of the above is shown below. In this example votes of all parties are divided by the series of divisors. From the resultant matrix, seats are allocated to parties with the highest votes.
| Party A |
Party B |
Party C |
Party D |
Total |
|
| Votes |
8700 |
6800 |
5200 |
3350 |
24 000 |
| Divide by 1 |
8700 (1) |
6800 (2) |
5200 (3) |
2350 |
|
| Divide by 2 |
4350 (4) |
3400 (5) |
2600 |
1675 |
|
| Divide by 3 |
2900 |
2267 |
1733 |
1117 |
|
| Seats |
2 |
2 |
1 |
0 |
A comparison of the examples shown under the d’Hondt version of the Highest Average system and the Largest Remainder shows a different distribution of seats and illustrates a characteristic of the d’Hondt version to favour major parties at the expense of minor parties. This can be modified by choosing different divisors. The Sainte-Lague version and the Modified Sainte-Lague version increase the size of the divisors, thus making it more difficult for a party to win each additional seat. The Sainte-Lague divisors are odd numbers beginning at one (e.g. 1, 3, 5, 7, etc). The modified Sainte-Lague numbers are 1.4, 3, 5, 7, 9. The Sainte-Lague divisors make it harder for major parties to gain each additional seat while the modified Sainte-Lague divisors maintain this characteristic as well as making it more difficult for smaller parties to gain representation through the 1.4 first divisor.
The following examples illustrate the Sainte-Lague characteristic of make it more difficult for major parties to obtain additional seats.
| Party A |
Party B |
Party C |
Party D |
Total |
|
| Votes |
8700 |
6800 |
5200 |
3350 |
24 000 |
| Divide by 1 |
8700 (1) |
6800 (2) |
5200 (3) |
3350 (4) |
|
| Divide by 3 |
2900 (5) |
2267 |
1733 |
1117 |
|
| Divide by 5 |
1740 |
1360 |
1040 |
670 |
Source: T. Mackie and R. Rose, The International Almanac of Electoral History, Facts on File, New York, 2nd ed. 1982
| Party A |
Party B |
Party C |
Party D |
Total |
|
| Votes |
8700 |
6800 |
5200 |
3350 |
24 000 |
| Divide by 1.4 |
6214 (1) |
4857 (2) |
3714 (3) |
2393 (5) |
|
| Divide by 3 |
2900 (4) |
2267 |
1733 |
1117 |
|
| Divide by 5 |
1740 |
1360 |
1040 |
670 |
Source: T. Mackie and R. Rose, The International Almanac of Electoral History, Facts on File, New York, 2nd ed. 1982
In the above example both the Sainte-Lague and modified Sainte-Lague versions produce the same distribution of seats. However, the two versions provide representation for the smallest party at the expense of the second largest party.
In addition to varying the first divisor to make the election of smaller parties more difficult, a threshold can also be used in List systems to achieve the same result. Thresholds require a party to achieve a certain percentage of the vote before they can be eligible to have members elected.
List systems of one variety are another are used widely throughout Western European nations including Austria, Belgium, Denmark, Finland, Italy, Netherlands, Norway, Sweden and Switzerland. In their work on national electoral systems, Reynolds and Reilly state that of 75 PR systems in use, all but nine use some form of List proportional representation system.(19) Among these are Belgium, Israel, Netherlands, Panama and Portugal. In Australia the ‘above-the-line’ feature in Senate ballot papers is typical of list systems. South Australia had a list system for its Legislative Council elections between 1973 and 1981.(20) Some examples allow a vote for individual candidates, but it is more common for voters only to be able to vote for a party list as a whole. An example of a List system that allows only a party vote is that used in Israel:
[120 to be elected]
| Party |
% |
Seats won in Knesset |
Proportion of total seats |
| Likud |
29.4 |
37 |
30.1 |
| Avoda (labour) |
14.5 |
19 |
15.9 |
| Shinui |
12.3 |
15 |
12.5 |
| Shas |
8.2 |
11 |
9.2 |
| National Union |
5.5 |
7 |
5.8 |
| Meretz |
5.2 |
6 |
5.0 |
| Mafdal |
4.2 |
5 |
4.2 |
| YhT |
4.3 |
5 |
4.2 |
| Hadash |
3.0 |
4 |
3.3 |
| Am Ekhad |
2.8 |
4 |
3.3 |
| Balad |
2.3 |
3 |
2.5 |
| YBA |
2.2 |
2 |
1.7 |
| United Arab List |
2.1 |
2 |
1.7 |
| AY |
1.2 |
- |
- |
| Herut |
1.2 |
- |
- |
Source: http://www.electionworld.org/election/israel.htm
The form of Proportional Representation familiar to most Australians is the Single Transferable Vote used in elections for the Senate, various Legislative Council elections, the Tasmanian House of Assembly and the ACT Legislative Assembly. The Tasmanian and ACT variant, colloquially known as Hare-Clark, differs from the system used for the Senate and the States’ upper houses in a number of ways. However, the basic concepts are the same.
Voting is in multi-member electorates. Voters are required to rank candidates in order of preference. This may involve the compulsory allocation of preferences to all candidates or may involve the allocation of a specified minimum number. In Tasmanian and ACT elections, for example, voters must allocate a number of preferences at least equal to the number of parliamentarians to be elected. Candidates are elected once they achieve the Droop quota of votes that is needed to be elected. The quota is based on the total number of votes cast and represents the smallest number of votes that will ensure election:
votes
Quota = ________________________ + 1
number to be elected + 1
In percentage terms this means that a vote of 14.3% is needed to win one of six Senate seats in a half-Senate election, or 7.7% in a double dissolution election. In a Tasmanian House Assembly election 16.7% is needed to win one of five seats in an electorate, while 8.3% will win one of 11 seats being contested in a half-Legislative Council in South Australia.
By a complicated method of counting preferences as well as surplus votes, vacancies are filled as candidates reach the quota. Any candidate whose first preference votes equal or exceed the quota are declared elected. Votes surplus to the quota that have been cast for successful candidates are transferred (at a reduced value) to the remaining candidates according to the second preferences recorded by the voters. As each candidate receives a quota the candidate is elected and the candidate’s surplus votes are distributed to candidates still in the count. If all surplus votes have been distributed and vacancies remain to be filled, the candidates with the smallest number of votes are gradually eliminated with those candidates’ votes being distributed among remaining candidates until all positions are filled.
[5 to be elected–winning candidates in bold]
Quota to be elected = 10 140 votes(16.7%)
| Candidate |
First preferences % |
Order of election |
| Green (ALP) |
17.0 |
1 |
| Kons (ALP) |
14.0 |
3 |
| Rockliff (Lib) |
13.1 |
2 |
| Best (ALP) |
10.6 |
4 |
| Gaffney (ALP) |
9.4 |
- |
| Whiteley (Lib) |
7.4 |
5 |
| O’Halloran (TG) |
6.5 |
- |
| Downie (Lib) |
5.7 |
- |
| Pattison(Lib) |
5.0 |
- |
| Thompson (TG) |
2.2 |
- |